If limx → 1 f(x) = 4, what is limx → 1 2·f(x)?
We "pull out'' the constant to find
limx → 1 2·f(x) = 2·limx → 1 f(x)= 2(4)= 8.
If limx → 2 4·f(x) = 12,
what is limx → 2 f(x)?
We don't have enough information to figure out what the function f is, but that's not important.We know that we're allowed to "pull out'' constants from limits, therefore
limx → 2 4·f(x) = 4·limx → 2 f(x).
Now we know
12 = limx → 2 4·f(x) = 4·limx → 2 f(x),
which means
limx → 2 f(x) = 3.
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