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SAT Math 2.3 Algebra and Functions. Calculate this function.
SAT Math 1.2 Algebra and Functions 359 Views
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Description:
SAT Math: Algebra and Functions Drill 1, Problem 2. Based on the data in the table, what is the maximum heart rate for the average 22-year-old?
- Functions / Translations
- Product Type / SAT Math
- Functions / Interpret functions that arise in applications
- Functions / Interpret functions that arise in applications
- Functions / Build a function that model a relationship between two quantities
- Functions / Build functions that model a relationship between two quantities
- Functions / Construct and compare linear, quadratic and exponential models
- Functions / Construct and compare linear, quadratic, and exponential models
- Functions / Interpret expressions for functions in terms of the situation they model
- Functions / Interpret expressions for functions in terms of the situation they model
- Functions / Interpret functions that arise in applications in terms of context
- Functions / Build a function that models a relationship between two quantities
- Functions / Construct and compare linear, quadratic, and exponential models
- Functions / Interpret functions that arise in applications
- Functions / Interpret functions that arise in applications
- Functions / Build a function that models a relationship between two quantities
- Functions / Construct and compare linear, quadratic, and exponential models
- Problem Solving and Data Analysis / Two-way table data
Transcript
- 00:02
And we're getting math-y with it...
- 00:04
The table below gives the average maximum heart rate,
- 00:07
by age, for a person exercising at full effort.
- 00:11
Based on the data in the table,
- 00:13
what is the maximum heart rate for the average 22-year-old?
Full Transcript
- 00:17
And here are your possible answers...
- 00:21
If we look at the data, as age increases by 5, average max heart rate decreases by 5.
- 00:28
Since age acts as our independent variable and average max
- 00:32
heart rate acts as our dependent variable,
- 00:38
we can calculate the change in average heart rate over age as the slope of our equation.
- 00:44
Which gives us negative 1.
- 00:46
The point slope form of a linear equation is y minus y1 equals slope times x minus x1.
- 00:54
h is y in this situation because it's the dependent variable, and a is x in this situation
- 01:01
because it's the independent variable.
- 01:04
We can take any x1 and y1 point to plug into the point-slope form of the equation...so
- 01:10
let's just take the points 20, 200.
- 01:13
We get h - 200 = -1(a - 20).
- 01:18
H minus 200 equals negative a plus 20.
- 01:22
Adding 200 to both sides of the equation... we have h equals 220 minus a.
- 01:27
We're looking for h given that a equals 22 years old.. so we get that h equals 198.
- 01:34
Answer's E.
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