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TSI Math: Working Backwards from the Midpoint Formula to Find an Endpoint 13 Views


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Description:

Point B is the midpoint of segment AC. The coordinates of A are (-9, 3) and the coordinates of B are (2, -3). What are the coordinates of C?


Transcript

00:03

Okay yes i mash bumpers another one up for you

00:06

On the coordinate plane point b is the midpoint of

00:08

segment A c coordinates of a r negative nine Three

00:12

The coordinates of b r two Negative three one of

00:15

coordinates of c We'll be is in the middle of

00:20

a c right there That's Why it's the midpoint Consider

00:23

the x and y coordinates separately So the ex coordinative

00:27

et is negative Nine The exporting and b is two

00:29

there's a horizontal distance They're of two minus negative nine

00:33

or eleven units between two points If we moved another

00:37

eleven units to the right well then we'd arrive at

00:39

the x coordinate of c rights We have two plus

00:43

eleven and thirteen so the x coordinate of sea is

00:46

thirteen So well now we'll do the same thing with

00:49

the y coordinates and get a cz Why coordinate up

00:52

three there Two b's Why coordinate of negative three We

00:55

need to move down three minus three that six units

00:59

moving over six units down to arrive at the negative

01:02

three months Six Well that's negative nine So sees why

01:05

coordinate their so put x and y coordinates back together

01:09

and we see that sea is located at the point

01:11

Thirteen negative nine and a is the answer Yeah we're 00:01:15.972 --> [endTime] shmoop

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